展开 (1+e^{2x})^2

解答

展开

(1 + e^{2 x})^{2}

1 + 2 e^{2 x} + e^{4 x}

求解步骤

(1 + e^{2 x})^{2}

使用完全平方公式:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = 1, b = e^{2 x}

= 1^{2} + 2 \cdot 1 \cdot e^{2 x} + (e^{2 x})^{2}

化简

1^{2} + 2 \cdot 1 \cdot e^{2 x} + (e^{2 x})^{2} : 1 + 2 e^{2 x} + e^{4 x}

= 1 + 2 e^{2 x} + e^{4 x}

e x p an d \frac{5 x - 13}{( x - 3 ) ( x - 2 )}

e x p an d (1 - sin (x)) (sec (x) + tan (x))

e x p an d (sec (x) + tan (x)) (1 - sin (x))

e x p an d (sec (x) - tan (x)) (csc (x) + 1)

e x p an d (π - x)^{2} - π