化简 (a-bi)^2

解答

化简

(a - bi)^{2}

(a^{2} - b^{2}) - 2 abi

求解步骤

(a - bi)^{2}

使用完全平方公式:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(a - bi)^{2} = a^{2} - 2 abi + (bi)^{2}

= a^{2} - 2 abi + (bi)^{2}

化简

(bi)^{2} : - b^{2}

= a^{2} - 2 abi - b^{2}

Rewrite in standard complex form:

(a^{2} - b^{2}) - 2 abi

= (a^{2} - b^{2}) - 2 abi

e x p an d (1 - cos (x))^{3}

e x p an d Ct an (π - x)

s im pl i f y (a - b) (a + b)

e x p an d \frac{( x + 3 ) ^{3}}{4 ( x - 1 ) ^{2}}

s im pl i f y (x^{4} + 2) (x^{4} - 2)