erweitern (2t-3)*e^{((t+2))/3}

Lösung

erweitern

(2 t - 3) \cdot e^{\frac{( t + 2 )}{3}}

2 e^{\frac{t + 2}{3}} t - 3 e^{\frac{t + 2}{3}}

Schritte zur Lösung

(2 t - 3) e^{\frac{( t + 2 )}{3}}

= e^{\frac{( t + 2 )}{3}} (2 t - 3)

Wende das Distributivgesetz an:

a (b - c) = ab - a c

a = e^{\frac{( t + 2 )}{3}}, b = 2 t, c = 3

= e^{\frac{( t + 2 )}{3}} \cdot 2 t - e^{\frac{( t + 2 )}{3}} \cdot 3

= 2 e^{\frac{( t + 2 )}{3}} t - 3 e^{\frac{( t + 2 )}{3}}

Entferne die Klammern:

(a) = a

= 2 e^{\frac{t + 2}{3}} t - 3 e^{\frac{t + 2}{3}}

e x p an d (x y^{2} + y) d x + (x - x^{2} y) d y

s im pl i f y x (x + 6) (x - 6)

\frac{\partial}{\partial x} ((z) (7 x + 8 y^{2}))

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