erweitern ((4n-1)^3)/8

Lösung

erweitern

\frac{( 4 n - 1 ) ^{3}}{8}

8 n^{3} - 6 n^{2} + \frac{3 n}{2} - \frac{1}{8}

Schritte zur Lösung

\frac{( 4 n - 1 ) ^{3}}{8}

(4 n - 1)^{3} = 64 n^{3} - 48 n^{2} + 12 n - 1

= \frac{64 n ^{3} - 48 n ^{2} + 12 n - 1}{8}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{64 n ^{3} - 48 n ^{2} + 12 n - 1}{8} = \frac{64 n ^{3}}{8} - \frac{48 n ^{2}}{8} + \frac{12 n}{8} - \frac{1}{8}

= \frac{64 n ^{3}}{8} - \frac{48 n ^{2}}{8} + \frac{12 n}{8} - \frac{1}{8}

Teile die Zahlen:

\frac{64}{8} = 8

= 8 n^{3} - \frac{48 n ^{2}}{8} + \frac{12 n}{8} - \frac{1}{8}

Teile die Zahlen:

\frac{48}{8} = 6

= 8 n^{3} - 6 n^{2} + \frac{12 n}{8} - \frac{1}{8}

Streiche

\frac{12 n}{8} : \frac{3 n}{2}

= 8 n^{3} - 6 n^{2} + \frac{3 n}{2} - \frac{1}{8}

e x p an d P (0, - 3) y Q (- 1, 7)

e x p an d \frac{1}{x ( x + 1 ) ( x + 2 )}

e x p an d \frac{20}{x ( x - 5 )}

\frac{d ^{2}}{d x ^{2}} ((y) (x^{3} + y^{3}))

e x p an d 3 (7 x - 1)^{5}