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Popular Álgebra >

simplificar (1-2i)^6

Solução

simplificar

(1 - 2 i)^{6}

Solução

117 - 44 i

Passos da solução

(1 - 2 i)^{6}

Aplicar o teorema do binômio:

(a + b)^{n} = i = 0 \sum n (i n) a^{(n - i)} b^{i}

a = 1, b = - 2 i

= i = 0 \sum 6 (i 6) \cdot 1^{(6 - i)} (- 2 i)^{i}

Expandir a soma

= \frac{6 !}{0 ! ( 6 - 0 ) !} \cdot 1^{6} (- 2 i)^{0} + \frac{6 !}{1 ! ( 6 - 1 ) !} \cdot 1^{5} (- 2 i)^{1} + \frac{6 !}{2 ! ( 6 - 2 ) !} \cdot 1^{4} (- 2 i)^{2} + \frac{6 !}{3 ! ( 6 - 3 ) !} \cdot 1^{3} (- 2 i)^{3} + \frac{6 !}{4 ! ( 6 - 4 ) !} \cdot 1^{2} (- 2 i)^{4} + \frac{6 !}{5 ! ( 6 - 5 ) !} \cdot 1^{1} (- 2 i)^{5} + \frac{6 !}{6 ! ( 6 - 6 ) !} \cdot 1^{0} (- 2 i)^{6}

Simplificar

\frac{6 !}{0 ! ( 6 - 0 ) !} \cdot 1^{6} (- 2 i)^{0} : 1

Simplificar

\frac{6 !}{1 ! ( 6 - 1 ) !} \cdot 1^{5} (- 2 i)^{1} : - 12 i

Simplificar

\frac{6 !}{2 ! ( 6 - 2 ) !} \cdot 1^{4} (- 2 i)^{2} : 60 i^{2}

Simplificar

\frac{6 !}{3 ! ( 6 - 3 ) !} \cdot 1^{3} (- 2 i)^{3} : - 160 i^{3}

Simplificar

\frac{6 !}{4 ! ( 6 - 4 ) !} \cdot 1^{2} (- 2 i)^{4} : 240 i^{4}

Simplificar

\frac{6 !}{5 ! ( 6 - 5 ) !} \cdot 1^{1} (- 2 i)^{5} : - 192 i^{5}

Simplificar

\frac{6 !}{6 ! ( 6 - 6 ) !} \cdot 1^{0} (- 2 i)^{6} : 64 i^{6}

= 1 - 12 i + 60 i^{2} - 160 i^{3} + 240 i^{4} - 192 i^{5} + 64 i^{6}

Simplificar

1 - 12 i + 60 i^{2} - 160 i^{3} + 240 i^{4} - 192 i^{5} + 64 i^{6} : - 44 i + 117

= - 44 i + 117

Rewrite in standard complex form:

117 - 44 i

= 117 - 44 i

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