|2x|>= 6

Lösung

∣ 2 x ∣ \geq 6

x \leq - 3 or x \geq 3

Intervall-Notation

(- \infty, - 3] \cup [3, \infty)

Schritte zur Lösung

∣ 2 x ∣ \geq 6

Wende Absoluteregel an: Wenn

∣ u ∣ \geq a, a > 0

dann

u \leq - a

u \geq a

2 x \leq - 6 or 2 x \geq 6

2 x \leq - 6 or 2 x \geq 6

x \leq - 3 or x \geq 3

y^{2} - 81 = 0

f a c t or x^{4} + 3 x^{2} - 28

∣ 3 x + 5 ∣ = 1

9 u^{2} + 25 = 30 u

∣ x + 2 ∣ = ∣ 2 - x ∣