erweitern 3/4 (3-x/9)-1/6 (1-x/3 =1-(x-3/2))

Lösung

erweitern

\frac{3}{4} (3 - \frac{x}{9}) - \frac{1}{6} (1 - \frac{x}{3} = 1 - (x - \frac{3}{2}))

\frac{25}{12} - \frac{x}{36} = \frac{3}{4} + \frac{x}{6}

Schritte zur Lösung

\frac{3}{4} (3 - \frac{x}{9}) - \frac{1}{6} (1 - \frac{x}{3} = 1 - (x - \frac{3}{2}))

= \frac{3}{4} (3 - \frac{x}{9}) - \frac{1}{6} (1 - 1 = \frac{x}{3} - (x - \frac{3}{2}))

Multipliziere aus

\frac{3}{4} (3 - \frac{x}{9}) : \frac{9}{4} - \frac{x}{12}

= \frac{9}{4} - \frac{x}{12} - \frac{1}{6} (1 - \frac{x}{3} = 1 - (x - \frac{3}{2}))

Multipliziere aus

- \frac{1}{6} (1 - \frac{x}{3} = 1 - (x - \frac{3}{2})) : - \frac{1}{6} + \frac{x}{18} = \frac{3}{4} + \frac{x}{6}

\frac{9}{4} - \frac{x}{12} - \frac{1}{6} + \frac{x}{18} = \frac{3}{4} + \frac{x}{6}

Multipliziere aus

\frac{9}{4} - \frac{x}{12} - \frac{1}{6} + \frac{x}{18} : \frac{25}{12} - \frac{x}{36}

\frac{25}{12} - \frac{x}{36} = \frac{3}{4} + \frac{x}{6}

s im pl i f y (2 + 3 x i)^{2}

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s im pl i f y (\frac{x}{2} - 1) (x - 3)

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e x p an d (3, - 3) y (- 1, 21)