What is expand (3+3sin(θ))^2 ?

The solution to expand (3+3sin(θ))^2 is 9+18sin(θ)+9sin^2(θ)

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expand (3+3sin(θ))^2

expand

(3 + 3 sin (θ))^{2}

9 + 18 sin (θ) + 9 sin^{2} (θ)

Solution steps

(3 + 3 sin (θ))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(3 + 3 sin (θ))^{2} = 3^{2} + 2 \cdot 3 \cdot 3 sin (θ) + (3 sin (θ))^{2}

= 3^{2} + 2 \cdot 3 \cdot 3 sin (θ) + (3 sin (θ))^{2}

Simplify

3^{2} + 2 \cdot 3 \cdot 3 sin (θ) + (3 sin (θ))^{2} : 9 + 18 sin (θ) + 9 sin^{2} (θ)

= 9 + 18 sin (θ) + 9 sin^{2} (θ)

(x + δ x)^{3}

(- 8, 8) y (1, - 10)

\frac{5}{6 ( - 2 y + 3 )}

(4.45 h^{2} d l - 3.16 d^{2} z t)^{3}

cos^{2} (x) (1 + tan^{2} (x) = 1)

What is expand (3+3sin(θ))^2 ?
The solution to expand (3+3sin(θ))^2 is 9+18sin(θ)+9sin^2(θ)