erweitern (2t-3)e^{(((t+2))/3)}

Lösung

erweitern

(2 t - 3) e^{(\frac{( t + 2 )}{3})}

2 e^{\frac{t + 2}{3}} t - 3 e^{\frac{t + 2}{3}}

Schritte zur Lösung

(2 t - 3) e^{(\frac{( t + 2 )}{3})}

= e^{(\frac{( t + 2 )}{3})} (2 t - 3)

Wende das Distributivgesetz an:

a (b - c) = ab - a c

a = e^{(\frac{( t + 2 )}{3})}, b = 2 t, c = 3

= e^{(\frac{( t + 2 )}{3})} \cdot 2 t - e^{(\frac{( t + 2 )}{3})} \cdot 3

= 2 e^{(\frac{( t + 2 )}{3})} t - 3 e^{(\frac{( t + 2 )}{3})}

Entferne die Klammern:

(a) = a

= 2 e^{\frac{t + 2}{3}} t - 3 e^{\frac{t + 2}{3}}

e x p an d \frac{2 ( x + 2 )}{x}

e x p an d (a + b) l e f t (a - b)

e x p an d (2 π + 16) \times 12

e x p an d \frac{1}{( 3 - x ) ^{4}}

e x p an d \frac{3 x ^{2} - x}{( x ^{2} - 3 ) ^{5}}