展开 (pi(-sqrt(3)+2))/(12)

解答

展开

\frac{π ( - 3 + 2 )}{12}

- \frac{π}{4 3} + \frac{π}{6}

十进制

0.07014 \dots

求解步骤

\frac{π ( - 3 + 2 )}{12}

乘开

π (- 3 + 2) : - 3 π + 2 π

= \frac{- 3 π + 2 π}{12}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 3 π + 2 π}{12} = - \frac{3 π}{12} + \frac{2 π}{12}

= - \frac{3 π}{12} + \frac{2 π}{12}

\frac{3 π}{12} = \frac{π}{4 3}

\frac{2 π}{12} = \frac{π}{6}

= - \frac{π}{4 3} + \frac{π}{6}

e x p an d (1 + tan (x))^{3} sec^{2} (x)

e x p an d (x^{\frac{1}{2}} + 1) (x^{\frac{1}{2}} - 1)

e x p an d (x - 4) \cdot (x + 2)

e x p an d \frac{9 x + 25}{( x + 3 ) ^{2}}

e x p an d \frac{x + 2}{( x + 3 ) ( x - 1 )}