What is (bsqrt(ax)-asqrt(bc))^2 ?

The solution to (bsqrt(ax)-asqrt(bc))^2 is b^2ax-2basqrt(ax)sqrt(bc)+ba^2c

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simplify (bsqrt(ax)-asqrt(bc))^2

simplify

(b a x - a b c)^{2}

b^{2} a x - 2 ba a x b c + b a^{2} c

Solution steps

(b a x - a b c)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(b a x - a b c)^{2} = (b a x)^{2} - 2 b a x a b c + (a b c)^{2}

= (b a x)^{2} - 2 b a x a b c + (a b c)^{2}

(b a x)^{2} = b^{2} a x

- 2 b a x a b c = - 2 ba a x b c

(a b c)^{2} = b a^{2} c

= b^{2} a x - 2 ba a x b c + b a^{2} c

f oco (4, - 3)

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\frac{6 x ^{2} - 2}{( x ^{2} + 1 ) ^{3}}

cos (2) (θ - \frac{π}{2})

\frac{e ^{- s}}{( s - 3 ) ( s - 2 ) s}

What is (bsqrt(ax)-asqrt(bc))^2 ?
The solution to (bsqrt(ax)-asqrt(bc))^2 is b^2ax-2basqrt(ax)sqrt(bc)+ba^2c