What is expand (x+1)sqrt(x^3-3x^2+6x+11) ?

The solution to expand (x+1)sqrt(x^3-3x^2+6x+11) is xsqrt(x^3-3x^2+6x+11)+sqrt(x^3-3x^2+6x+11)

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expand (x+1)sqrt(x^3-3x^2+6x+11)

expand

(x + 1) x^{3} - 3 x^{2} + 6 x + 11

x x^{3} - 3 x^{2} + 6 x + 11 + x^{3} - 3 x^{2} + 6 x + 11

Solution steps

(x + 1) x^{3} - 3 x^{2} + 6 x + 11

= x^{3} - 3 x^{2} + 6 x + 11 (x + 1)

Apply the distributive law:

a (b + c) = ab + a c

x^{3} - 3 x^{2} + 6 x + 11 (x + 1) = x^{3} - 3 x^{2} + 6 x + 11 x + x^{3} - 3 x^{2} + 6 x + 11 \cdot 1

= x^{3} - 3 x^{2} + 6 x + 11 x + x^{3} - 3 x^{2} + 6 x + 11 \cdot 1

Simplify

x^{3} - 3 x^{2} + 6 x + 11 x + x^{3} - 3 x^{2} + 6 x + 11 \cdot 1 : x x^{3} - 3 x^{2} + 6 x + 11 + x^{3} - 3 x^{2} + 6 x + 11

= x x^{3} - 3 x^{2} + 6 x + 11 + x^{3} - 3 x^{2} + 6 x + 11

\frac{( x + i y ) ^{5}}{( x ^{2} + y ^{2} ) ^{2}}

\frac{2 s + 1}{( s + 1 ) ( s ^{2} + 2 s + 2 )}

\frac{2 s + 5}{( s + 3 ) ^{2} + 25}

(3 x + \frac{1}{4}) (3 x - \frac{1}{4})

\frac{3 ( a - 1 )}{a}

What is expand (x+1)sqrt(x^3-3x^2+6x+11) ?
The solution to expand (x+1)sqrt(x^3-3x^2+6x+11) is xsqrt(x^3-3x^2+6x+11)+sqrt(x^3-3x^2+6x+11)