展开 pi(r_{0}-at)^2

解答

展开

π (r_{0} - a t)^{2}

π r_{0}^{2} - 2 πa r_{0} t + π a^{2} t^{2}

求解步骤

π (r_{0} - a t)^{2}

(r_{0} - a t)^{2} = r_{0}^{2} - 2 a r_{0} t + a^{2} t^{2}

= π (r_{0}^{2} - 2 a r_{0} t + a^{2} t^{2})

打开括号

= π r_{0}^{2} + π (- 2 a r_{0} t) + π a^{2} t^{2}

使用加减运算法则

+ (- a) = - a

= π r_{0}^{2} - 2 πa r_{0} t + π a^{2} t^{2}

e x p an d \frac{2 x ^{2} + 5}{( x ^{2} + 1 ) ^{2}}

e x p an d (s + 0.33 + 2.23 i) (s + 0.33 - 2.23 i)

e x p an d \frac{224 ( 742 + 104689 )}{5945}

e x p an d \frac{( x ^{5} )}{( x - 2 ) ^{2}}

e x p an d \frac{10 ( s + 5 )}{s ^{2} + 3 s + 2}