What is expand (y^3+kxy^4-10x)dx+(3xy^2+29x^2y^3) ?

The solution to expand (y^3+kxy^4-10x)dx+(3xy^2+29x^2y^3) is y^3dx+ky^4xdx-10xdx+3xy^2+29x^2y^3

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expand (y^3+kxy^4-10x)dx+(3xy^2+29x^2y^3)

expand

(y^{3} + k x y^{4} - 10 x) d x + (3 x y^{2} + 29 x^{2} y^{3})

y^{3} d x + k y^{4} x d x - 10 x d x + 3 x y^{2} + 29 x^{2} y^{3}

Solution steps

(y^{3} + k x y^{4} - 10 x) d x + (3 x y^{2} + 29 x^{2} y^{3})

= (y^{3} + k y^{4} x - 10 x) d x + (3 y^{2} x + 29 y^{3} x^{2})

Expand

d x (y^{3} + k x y^{4} - 10 x) : y^{3} d x + k y^{4} x d x - 10 x d x

= y^{3} d x + k y^{4} x d x - 10 x d x + (3 x y^{2} + 29 x^{2} y^{3})

Remove parentheses:

(a) = a

= y^{3} d x + k y^{4} x d x - 10 x d x + 3 x y^{2} + 29 x^{2} y^{3}

\frac{d}{d x} ((2 - x^{2}) cos (x^{2})) + 2 x sin (x^{2})

(1 + tan (x))^{3}

\frac{( ( 3 s - 1 ) ( 2 s - 1 ) )}{( s ( s ^{2} - 2 s + 14 ) )}

\frac{s - 1}{( s + 1 ) ( s + 2 ) ( s + 3 ) ( s + 4 )}

\frac{7}{( x + 1 ) ^{2}}

What is expand (y^3+kxy^4-10x)dx+(3xy^2+29x^2y^3) ?
The solution to expand (y^3+kxy^4-10x)dx+(3xy^2+29x^2y^3) is y^3dx+ky^4xdx-10xdx+3xy^2+29x^2y^3