erweitern 12(2+(2i)/n)^2-9

Lösung

erweitern

12 (2 + \frac{2 i}{n})^{2} - 9

(- \frac{48}{n ^{2}} + 39) + \frac{96}{n} i

Schritte zur Lösung

12 (2 + \frac{2 i}{n})^{2} - 9

Schreibe

12 (2 + \frac{2 i}{n})^{2}

um:

48 - \frac{48}{n ^{2}} + \frac{96}{n} i

= 48 - \frac{48}{n ^{2}} + \frac{96}{n} i - 9

Füge zusammen:

48 - \frac{48}{n ^{2}} + \frac{96}{n} i - 9 : - \frac{48}{n ^{2}} + \frac{96}{n} i + 39

= - \frac{48}{n ^{2}} + \frac{96}{n} i + 39

Rewrite in standard complex form:

(- \frac{48}{n ^{2}} + 39) + \frac{96}{n} i

= (- \frac{48}{n ^{2}} + 39) + \frac{96}{n} i

e x p an d \frac{( - x + 6 ) ^{2}}{6}

e x p an d x \cdot (csc (x) + cot (x)) - cos (x)

e x p an d \frac{3 x ^{2} ( x + 3 ) - x ( x ^{3} + 2 )}{( x + 3 ) ^{2}}

e x p an d D x [(1 + x^{2}) (1 + 2 x^{2})]