erweitern (2-x^{1/3})^2

Lösung

erweitern

(2 - x^{\frac{1}{3}})^{2}

4 - 4 x^{\frac{1}{3}} + x^{\frac{2}{3}}

Schritte zur Lösung

(2 - x^{\frac{1}{3}})^{2}

Wende Formel für perfekte quadratische Gleichungen an:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(2 - x^{\frac{1}{3}})^{2} = 2^{2} - 2 \cdot 2 x^{\frac{1}{3}} + (x^{\frac{1}{3}})^{2}

= 2^{2} - 2 \cdot 2 x^{\frac{1}{3}} + (x^{\frac{1}{3}})^{2}

2^{2} = 4

2 \cdot 2 x^{\frac{1}{3}} = 4 x^{\frac{1}{3}}

(x^{\frac{1}{3}})^{2} = x^{\frac{2}{3}}

= 4 - 4 x^{\frac{1}{3}} + x^{\frac{2}{3}}

e x p an d \frac{( x + 1 ) ( x ^{2} + x + 1 )}{( x + 2 )}

e x p an d (x + \frac{1}{y})^{7}

s im pl i f y (x - \frac{3}{2}) \cdot (x + \frac{1}{2})

e x p an d tan^{2} (a) (2 cos^{2} (a) + sin^{2} (a - 1))

e x p an d A (3, - 3) y B (0, 3)