展开 ((x^2-16)(x^2+6x+8))/((x-1)(x^2+2x-3))

解答

展开

\frac{( x ^{2} - 16 ) ( x ^{2} + 6 x + 8 )}{( x - 1 ) ( x ^{2} + 2 x - 3 )}

\frac{x ^{4} + 6 x ^{3} - 8 x ^{2} - 96 x - 128}{x ^{3} + x ^{2} - 5 x + 3}

求解步骤

\frac{( x ^{2} - 16 ) ( x ^{2} + 6 x + 8 )}{( x - 1 ) ( x ^{2} + 2 x - 3 )}

乘开

(x - 1) (x^{2} + 2 x - 3) : x^{3} + x^{2} - 5 x + 3

= \frac{( x ^{2} - 16 ) ( x ^{2} + 6 x + 8 )}{x ^{3} + x ^{2} - 5 x + 3}

乘开

(x^{2} - 16) (x^{2} + 6 x + 8) : x^{4} + 6 x^{3} - 8 x^{2} - 96 x - 128

= \frac{x ^{4} + 6 x ^{3} - 8 x ^{2} - 96 x - 128}{x ^{3} + x ^{2} - 5 x + 3}

e x p an d \frac{d ^{2} y}{d ^{2} x} (x^{2} + y^{2} = 25)

\frac{d}{d t} ((x) (a (a t^{2} + b t + c) + b)^{r (x, t)})

e x p an d \frac{2 x - 4}{( x ^{2} + x ) \cdot ( x ^{2} + 1 )}

e x p an d \frac{5 ( - 2 y + 3 )}{6}

s im pl i f y (t - sin (t)) (sin (t))