What is expand (2(2x-3))/(9x^2(x+1)) ?

The solution to expand (2(2x-3))/(9x^2(x+1)) is (4x-6)/(9x^3+9x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2(2x-3))/(9x^2(x+1))

expand

\frac{2 ( 2 x - 3 )}{9 x ^{2} ( x + 1 )}

\frac{4 x - 6}{9 x ^{3} + 9 x ^{2}}

Solution steps

\frac{2 ( 2 x - 3 )}{9 x ^{2} ( x + 1 )}

Expand

9 x^{2} (x + 1) : 9 x^{3} + 9 x^{2}

= \frac{2 ( 2 x - 3 )}{9 x ^{3} + 9 x ^{2}}

Expand

2 (2 x - 3) : 4 x - 6

= \frac{4 x - 6}{9 x ^{3} + 9 x ^{2}}

\frac{( x - 4 ) ( x + 2 )}{( x + 8 ) ( x + 1 )}

(x - i)^{2}

\frac{9 ( - 189 π + 1620 )}{10}

(sin (y) - y sin (x)) d x + (cos (x) + x cos (y) - y) d y

\frac{10 x + 0.5}{( x ^{2} - 1.2 x + 0.2 ) ( x - 1 )}

What is expand (2(2x-3))/(9x^2(x+1)) ?
The solution to expand (2(2x-3))/(9x^2(x+1)) is (4x-6)/(9x^3+9x^2)