展开 1/2 cos^3(t)(1-tan^4(t)+sec^4(t))

解答

展开

\frac{1}{2} cos^{3} (t) (1 - tan^{4} (t) + sec^{4} (t))

\frac{cos ^{3} ( t ) - cos ^{3} ( t ) tan ^{4} ( t ) + cos ^{3} ( t ) sec ^{4} ( t )}{2}

求解步骤

\frac{1}{2} cos^{3} (t) (1 - tan^{4} (t) + sec^{4} (t))

使用分配律:

m (a + b + c) = ma + mb + m c

\frac{1}{2} cos^{3} (t) (1 - tan^{4} (t) + sec^{4} (t)) = \frac{1}{2} cos^{3} (t) \cdot 1 + \frac{1}{2} cos^{3} (t) (- tan^{4} (t)) + \frac{1}{2} cos^{3} (t) sec^{4} (t)

= \frac{1}{2} cos^{3} (t) \cdot 1 + \frac{1}{2} cos^{3} (t) (- tan^{4} (t)) + \frac{1}{2} cos^{3} (t) sec^{4} (t)

化简

\frac{1}{2} cos^{3} (t) \cdot 1 + \frac{1}{2} cos^{3} (t) (- tan^{4} (t)) + \frac{1}{2} cos^{3} (t) sec^{4} (t) : \frac{cos ^{3} ( t ) - cos ^{3} ( t ) tan ^{4} ( t ) + cos ^{3} ( t ) sec ^{4} ( t )}{2}

= \frac{cos ^{3} ( t ) - cos ^{3} ( t ) tan ^{4} ( t ) + cos ^{3} ( t ) sec ^{4} ( t )}{2}

e x p an d cos (x) (2 sin (x) - 1)

s im pl i f y ((V - \frac{k \cdot c}{t \cdot s + 1}) A) F

e x p an d x^{\frac{4}{5}} (8 x - 32)^{2}

e x p an d \frac{x - 1}{( x + 1 ) ( x - 3 )}

e x p an d (0, 4) y (0, - 4)