展开 (2(j+k+5))/(9(3f+3k+15))

解答

展开

\frac{2 ( j + k + 5 )}{9 ( 3 f + 3 k + 15 )}

\frac{2 j + 2 k + 10}{27 f + 27 k + 135}

求解步骤

\frac{2 ( j + k + 5 )}{9 ( 3 f + 3 k + 15 )}

乘开

9 (3 f + 3 k + 15) : 27 f + 27 k + 135

= \frac{2 ( j + k + 5 )}{27 f + 27 k + 135}

乘开

2 (j + k + 5) : 2 j + 2 k + 10

= \frac{2 j + 2 k + 10}{27 f + 27 k + 135}

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