展开 ((2(t^2+1)^2),-t(t^2+1))*(1,2t)

解答

展开

((2 (t^{2} + 1)^{2}), - t (t^{2} + 1)) \cdot (1, 2 t)

(1 \cdot 2, t) (2 (t^{2} + 1)^{2}), - t^{2} t (1 \cdot 2, t) - 1 \cdot t (1 \cdot 2, t)

求解步骤

((2 (t^{2} + 1)^{2}), - t (t^{2} + 1)) (1, 2 t)

= (, (2 (t^{2} + 1)^{2}) - t (t^{2} + 1)) (1 \cdot 2, t)

乘开

(1, 2 t) ((2 (t^{2} + 1)^{2}), - t (t^{2} + 1)) : (1 \cdot 2, t) (2 (t^{2} + 1)^{2}), - t (1 \cdot 2, t) (t^{2} + 1)

= (1 \cdot 2, t) (2 (t^{2} + 1)^{2}), - t (1 \cdot 2, t) (t^{2} + 1)

乘开

- t (1 \cdot 2, t) (t^{2} + 1) : - t^{2} t (1 \cdot 2, t) - 1 \cdot t (1 \cdot 2, t)

= (1 \cdot 2, t) (2 (t^{2} + 1)^{2}), - t^{2} t (1 \cdot 2, t) - 1 \cdot t (1 \cdot 2, t)

e x p an d \frac{- x ^{2} - 3 x - 10}{( x + 2 ) ( x + 4 ) ( x - 2 )}

e x p an d e^{x} (x^{2} + 2 x)

e x p an d - 2 (x + 1) (u^{'} (x) + H (x))

e x p an d \frac{\frac{d}{d x} ( ( x + 2 ) ( x - 1 ) )}{x ^{3} - 1}

e x p an d \frac{( x + 1 ) ( x - 3 ) 3}{( x + 4 ) ( x - 1 )}