展开 (B+BC)(B+B^'C)(B+D)

解答

展开

(B + BC) (B + B^{^{'}} C) (B + D)

B^{3} + D B^{2} + C B^{' + 2} + D C B^{1 +'} + B^{3} C + D B^{2} C + C^{2} B^{' + 2} + D C^{2} B^{1 +'}

求解步骤

(B + BC) (B + B^{^{'}} C) (B + D)

= (B + BC) (B + C B^{^{^{'}}}) (B + D)

乘开

(B + BC) (B + B^{^{'}} C) : B^{2} + C B^{1 +^{'}} + B^{2} C + C^{2} B^{1 +^{'}}

= (B^{2} + C B^{1 +^{'}} + B^{2} C + C^{2} B^{1 +^{'}}) (B + D)

乘开

(B^{2} + C B^{1 +^{'}} + B^{2} C + C^{2} B^{1 +^{'}}) (B + D) : B^{3} + D B^{2} + C B^{^{'} + 2} + D C B^{1 +^{'}} + B^{3} C + D B^{2} C + C^{2} B^{^{'} + 2} + D C^{2} B^{1 +^{'}}

= B^{3} + D B^{2} + C B^{^{'} + 2} + D C B^{1 +^{'}} + B^{3} C + D B^{2} C + C^{2} B^{^{'} + 2} + D C^{2} B^{1 +^{'}}

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