erweitern (1/k y+b/2)^2

Lösung

erweitern

(\frac{1}{k} y + \frac{b}{2})^{2}

\frac{4 y ^{2} + 4 y bk + b ^{2} k ^{2}}{4 k ^{2}}

Schritte zur Lösung

(\frac{1}{k} y + \frac{b}{2})^{2}

Wende Formel für perfekte quadratische Gleichungen an:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(\frac{1}{k} y + \frac{b}{2})^{2} = (\frac{1}{k} y)^{2} + 2 \cdot \frac{1}{k} y \frac{b}{2} + (\frac{b}{2})^{2}

= (\frac{1}{k} y)^{2} + 2 \cdot \frac{1}{k} y \frac{b}{2} + (\frac{b}{2})^{2}

Vereinfache

(\frac{1}{k} y)^{2} + 2 \cdot \frac{1}{k} y \frac{b}{2} + (\frac{b}{2})^{2} : \frac{4 y ^{2} + 4 y bk + b ^{2} k ^{2}}{4 k ^{2}}

= \frac{4 y ^{2} + 4 y bk + b ^{2} k ^{2}}{4 k ^{2}}

e x p an d \frac{5 ( x - 2 )}{3}

e x p an d π (- 16 + x^{2})

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e x p an d \frac{2 - x}{x ^{2} + 4 x + 4} + \frac{1}{x + 2}

e x p an d \frac{2 n + 1}{n ( n + 1 )}