展开-4(2xe^{2x}+e^{2x}*2x^2)

解答

展开

- 4 (2 x e^{2 x} + e^{2 x} \cdot 2 x^{2})

- 8 e^{2 x} x - 8 e^{2 x} x^{2}

求解步骤

- 4 (2 x e^{2 x} + e^{2 x} \cdot 2 x^{2})

= - 4 (2 e^{2 x} x + 2 e^{2 x} x^{2})

使用分配律:

a (b + c) = ab + a c

a = - 4, b = 2 x e^{2 x}, c = e^{2 x} \cdot 2 x^{2}

= - 4 \cdot 2 x e^{2 x} + (- 4) e^{2 x} \cdot 2 x^{2}

使用加减运算法则

+ (- a) = - a

= - 4 \cdot 2 e^{2 x} x - 4 \cdot 2 e^{2 x} x^{2}

数字相乘:

4 \cdot 2 = 8

= - 8 e^{2 x} x - 8 e^{2 x} x^{2}

e x p an d lo g_{2} (8 x^{(2)} + 80 x + 200)

e x p an d \frac{( s + 2 ) ^{2}}{s ( s + 1 ) ^{3}}

e x p an d 2 (4 x)

e x p an d \frac{( x - 1 ) ( x ^{2} + x + 1 )}{x ^{3}}

e x p an d \frac{π ( 7 - 13 )}{36} (e^{729} - 1)