erweitern 2x^{2/3}(x+3)

Lösung

erweitern

2 x^{\frac{2}{3}} (x + 3)

2 x^{\frac{5}{3}} + 6 x^{\frac{2}{3}}

Schritte zur Lösung

2 x^{\frac{2}{3}} (x + 3)

Wende das Distributivgesetz an:

a (b + c) = ab + a c

2 x^{\frac{2}{3}} (x + 3) = 2 x^{\frac{2}{3}} x + 2 x^{\frac{2}{3}} \cdot 3

= 2 x^{\frac{2}{3}} x + 2 x^{\frac{2}{3}} \cdot 3

2 x^{\frac{2}{3}} x = 2 x^{\frac{5}{3}}

2 x^{\frac{2}{3}} \cdot 3 = 6 x^{\frac{2}{3}}

= 2 x^{\frac{5}{3}} + 6 x^{\frac{2}{3}}

s im pl i f y x (x + y)

s im pl i f y (ab + \frac{9}{2}) (- \frac{9}{2} + ab)

e x p an d tan^{2} (x) - sin^{2} (x) (cot^{2} (x) + tan (x))^{2}

e x p an d \frac{2 x ( x + 1 ) ( x - 1 )}{x ^{4} + 6 x ^{2} + 1}

e x p an d \frac{7}{( x - 1 ) ( x + 2 )}