化简 (7+sin(t))^2+cos^2(t)

解答

化简

(7 + sin (t))^{2} + cos^{2} (t)

14 sin (t) + 50

求解步骤

(7 + sin (t))^{2} + cos^{2} (t)

展开

(7 + sin (t))^{2} : 49 + 14 sin (t) + sin^{2} (t)

= 49 + 14 sin (t) + sin^{2} (t) + cos^{2} (t)

使用毕达哥拉斯恒等式:

cos^{2} (x) + sin^{2} (x) = 1

= 14 sin (t) + 49 + 1

数字相加:

49 + 1 = 50

= 14 sin (t) + 50

e x p an d (6 x + 4) (x + 1)

e x p an d 2 (x + y) (1 + y^{'} (x))

s im pl i f y (9 x - 1 - 6)^{2}

e x p an d \frac{2 t ( t - 2 )}{e ^{t} t}

e x p an d \frac{20 ( 5 + 3 x )}{1 + 0.04 x}