展开 y^{1/3}(y^{4/9}-7y^{2/9})

解答

展开

y^{\frac{1}{3}} (y^{\frac{4}{9}} - 7 y^{\frac{2}{9}})

y^{\frac{7}{9}} - 7 y^{\frac{5}{9}}

求解步骤

y^{\frac{1}{3}} (y^{\frac{4}{9}} - 7 y^{\frac{2}{9}})

使用分配律:

a (b - c) = ab - a c

y^{\frac{1}{3}} (y^{\frac{4}{9}} - 7 y^{\frac{2}{9}}) = y^{\frac{1}{3}} y^{\frac{4}{9}} - y^{\frac{1}{3}} \cdot 7 y^{\frac{2}{9}}

= y^{\frac{1}{3}} y^{\frac{4}{9}} - y^{\frac{1}{3}} \cdot 7 y^{\frac{2}{9}}

y^{\frac{1}{3}} y^{\frac{4}{9}} = y^{\frac{7}{9}}

y^{\frac{1}{3}} \cdot 7 y^{\frac{2}{9}} = 7 y^{\frac{5}{9}}

= y^{\frac{7}{9}} - 7 y^{\frac{5}{9}}

e x p an d e^{x} cos (x) (e^{x} cos (x) + e^{x} sin (x))

e x p an d \frac{x}{( x - 2 ) ( x + 2 )}

e x p an d 3 cos (t) sin (t) - (2 t - 5)^{2} sin (t) + 3 t

f (x) = \frac{1}{( x - 1 ) ^{5}}

e x p an d - (x - 2) e^{2 x}