展开 (e^{2pi}-1)(e^{2pi}+1)

解答

展开

(e^{2 π} - 1) (e^{2 π} + 1)

e^{4 π} - 1

十进制

286750.31313 \dots

求解步骤

(e^{2 π} - 1) (e^{2 π} + 1)

使用平方差公式:

(a - b) (a + b) = a^{2} - b^{2}

a = e^{2 π}, b = 1

= (e^{2 π})^{2} - 1^{2}

化简

(e^{2 π})^{2} - 1^{2} : e^{4 π} - 1

= e^{4 π} - 1

e x p an d A (1, - 1) B (- 7, 3)

e x p an d \frac{10 - ( x - 4 ) x ( x ^{2} - 3 x - 2 )}{( x - 4 ) x}

s im pl i f y (4 x - 8 y) (4 x + 8 y)

e x p an d (6 x^{4} - 5 x^{2} - 7) l e f t (- 4 x^{3})

s im pl i f y 15 (\frac{2}{5} + 3 u)