erweitern (x+1)ln(x)

Lösung

erweitern

(x + 1) ln (x)

x ln (x) + ln (x)

Schritte zur Lösung

(x + 1) ln (x)

= ln (x) (x + 1)

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = ln (x), b = x, c = 1

= ln (x) x + ln (x) \cdot 1

= x ln (x) + 1 \cdot ln (x)

Multipliziere:

1 \cdot ln (x) = ln (x)

= x ln (x) + ln (x)

e x p an d \frac{( u - 1 ) ^{2}}{u}

e x p an d \frac{\partial}{\partial x} (6 (2 x + y)^{2} \cdot (x - 2 y)) + (2 x + y)^{3}

e x p an d \frac{a x}{( x + a ) ( x - a )}

e x p an d ln (1 + 2 x) + e^{2 x - x^{2}} (3 x + 1 - 1)

e x p an d (x - 49) (x + 7)