簡約 1/2 (θ+(sin(2θ))/2)

解

簡約

\frac{1}{2} (θ + \frac{sin ( 2 θ )}{2})

\frac{2 θ + sin ( 2 θ )}{4}

解答ステップ

\frac{1}{2} (θ + \frac{sin ( 2 θ )}{2})

結合

θ + \frac{sin ( 2 θ )}{2} : \frac{θ \cdot 2 + sin ( 2 θ )}{2}

= \frac{1}{2} \cdot \frac{θ \cdot 2 + sin ( 2 θ )}{2}

= \frac{1}{2} \cdot \frac{2 θ + sin ( 2 θ )}{2}

分数の規則を適用する:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot ( 2 θ + sin ( 2 θ ) )}{2 \cdot 2}

規則を適用する:

1 \cdot a = a

1 \cdot (2 θ + sin (2 θ)) = (2 θ + sin (2 θ))

= \frac{2 θ + sin ( 2 θ )}{2 \cdot 2}

数を乗じる:

2 \cdot 2 = 4

= \frac{2 θ + sin ( 2 θ )}{4}