展開する sinh((x-b)(x-c))(2x-c-b)

解

展開する

sinh ((x - b) (x - c)) (2 x - c - b)

2 x sinh ((x - b) (x - c)) - c sinh ((x - b) (x - c)) - b sinh ((x - b) (x - c))

解答ステップ

sinh ((x - b) (x - c)) (2 x - c - b)

分配法則を適用する:

m (a + b + c) = ma + mb + m c

sinh ((x - b) (x - c)) (2 x - c - b) = sinh ((x - b) (x - c)) \cdot 2 x + sinh ((x - b) (x - c)) (- c) + sinh ((x - b) (x - c)) (- b)

= sinh ((x - b) (x - c)) \cdot 2 x + sinh ((x - b) (x - c)) (- c) + sinh ((x - b) (x - c)) (- b)

簡素化

sinh ((x - b) (x - c)) \cdot 2 x + sinh ((x - b) (x - c)) (- c) + sinh ((x - b) (x - c)) (- b) : 2 x sinh ((x - b) (x - c)) - c sinh ((x - b) (x - c)) - b sinh ((x - b) (x - c))

= 2 x sinh ((x - b) (x - c)) - c sinh ((x - b) (x - c)) - b sinh ((x - b) (x - c))