erweitern (2x+y=1,6)(x+y=10)

Lösung

erweitern

(2 x + y = 1, 6) (x + y = 10)

2 x^{2} + 2 x y = 10

Schritte zur Lösung

(2 x + y = 1, 6) (x + y = 10)

= (2 x + 1 \cdot 6 =, y) (x + 10 = y)

Wende Ausklammerungsregel an (VANI):

(a + b) (c + d) = a c + a d + b c + b d

a = 2 x, b = y = 1, 6, c = x, d = y = 10

2 xx + 2 x y = 10 + y = 1, 6 x + y = 1, 6 y = 10

Multipliziere aus

2 xx + 2 x y : 2 x^{2} + 2 x y

2 x^{2} + 2 x y = 10

e x p an d \frac{2 x ( x ^{2} - 3 ) ^{4}}{625}

e x p an d x e^{3 x} (4 - 2 x) - 2

\frac{d ^{2}}{d x ^{2}} ((g (x, y)) (x^{2} y + cos (y) + y, x))

e x p an d (5 4 x + x) (2 x^{3} - 3 x^{2} + x - 1)

e x p an d (5 x^{3} + x^{2} + x) (1.5 x^{2} + 3)