展开 (2x+y=1,6)(x+y=10)

解答

展开

(2 x + y = 1, 6) (x + y = 10)

2 x^{2} + 2 x y = 10

求解步骤

(2 x + y = 1, 6) (x + y = 10)

= (2 x + 1 \cdot 6 =, y) (x + 10 = y)

使用 FOIL 方法:

(a + b) (c + d) = a c + a d + b c + b d

a = 2 x, b = y = 1, 6, c = x, d = y = 10

2 xx + 2 x y = 10 + y = 1, 6 x + y = 1, 6 y = 10

乘开

2 xx + 2 x y : 2 x^{2} + 2 x y

2 x^{2} + 2 x y = 10

e x p an d \frac{2 x ( x ^{2} - 3 ) ^{4}}{625}

e x p an d x e^{3 x} (4 - 2 x) - 2

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e x p an d (5 x^{3} + x^{2} + x) (1.5 x^{2} + 3)