展开 (X^4-2X^2+2)left(X^2-2X+3)

解答

展开

(X^{4} - 2 X^{2} + 2) l e f t (X^{2} - 2 X + 3)

e l X^{6} f t - 2 e l X^{5} f t + e l X^{4} f t + 4 e l X^{3} f t - 4 e l X^{2} f t - 4 e lX f t + 6 e l f t

求解步骤

(X^{4} - 2 X^{2} + 2) l e f t (X^{2} - 2 X + 3)

= e l f t (X^{4} - 2 X^{2} + 2) (X^{2} - 2 X + 3)

乘开

(X^{4} - 2 X^{2} + 2) (X^{2} - 2 X + 3) : X^{6} - 2 X^{5} + X^{4} + 4 X^{3} - 4 X^{2} - 4 X + 6

= l e f t (X^{6} - 2 X^{5} + X^{4} + 4 X^{3} - 4 X^{2} - 4 X + 6)

乘开

l e f t (X^{6} - 2 X^{5} + X^{4} + 4 X^{3} - 4 X^{2} - 4 X + 6) : e l X^{6} f t - 2 e l X^{5} f t + e l X^{4} f t + 4 e l X^{3} f t - 4 e l X^{2} f t - 4 e lX f t + 6 e l f t

= e l X^{6} f t - 2 e l X^{5} f t + e l X^{4} f t + 4 e l X^{3} f t - 4 e l X^{2} f t - 4 e lX f t + 6 e l f t

e x p an d - \frac{- sin ( θ ) + x cos ( θ )}{( cos ( θ ) + x sin ( θ ) ) ^{2}}

s im pl i f y e^{(1 + 2 i) x}

e x p an d (1 - t) (4, 6, 6) + t (6, 7, 2)

s im pl i f y (3 x - 5 \circ - 4 x - 2) (- 5)

e x p an d (x + y - 1) d x