展开 (e-2,e+1)*(x,y)

解答

展开

(e - 2, e + 1) \cdot (x, y)

e (, x y) - 2 (, x y), e + 1 \cdot (, x y)

求解步骤

(e - 2, e + 1) (x, y)

= (e - 2 e, + 1) (, x y)

打开括号

= (x, y) e + (x, y) (- 2, e) + (x, y) \cdot 1

使用加减运算法则

+ (- a) = - a

= e (, x y) - 2 (, x y), e + 1 \cdot (, x y)

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