展开 (-1/2)(1/2 (1-x)-1/4)

解答

展开

(- \frac{1}{2}) (\frac{1}{2} (1 - x) - \frac{1}{4})

- \frac{1 - x}{4} + \frac{1}{8}

求解步骤

(- \frac{1}{2}) (\frac{1}{2} (1 - x) - \frac{1}{4})

使用法则:

(- a) = - a

(- \frac{1}{2}) = - \frac{1}{2}

= - \frac{1}{2} (\frac{1}{2} (1 - x) - \frac{1}{4})

使用分配律:

a (b - c) = ab - a c

- \frac{1}{2} (\frac{1}{2} (1 - x) - \frac{1}{4}) = - \frac{1}{2} \cdot \frac{1}{2} (1 - x) - (- \frac{1}{2}) \frac{1}{4}

= - \frac{1}{2} \cdot \frac{1}{2} (1 - x) - (- \frac{1}{2}) \frac{1}{4}

化简

- \frac{1}{2} \cdot \frac{1}{2} (1 - x) - (- \frac{1}{2}) \frac{1}{4} : - \frac{1 - x}{4} + \frac{1}{8}

= - \frac{1 - x}{4} + \frac{1}{8}

s im pl i f y \frac{1}{8} (x - \frac{1}{28} sin (28 x))

e x p an d (sin (y) - y sin (x)) d x + (cos (x) + x cos (y))

s im pl i f y - i (x + i y)^{2}

e x p an d - \frac{2}{( x - 1 ) ^{2} ( x + 1 ) ^{2}}

e x p an d (- y^{3} + y) d y