解
展開する (21a+32a54)12
解
4096a6+256a1063+38411a533+43255a1069+14455a536+2722a215+243308a539+352a1081+729880a542+1968314080a1087+5632a9+590494096a1093+5314414096a548
解答ステップ
(21a+32a54)12
2項定理を適用する: (a+b)n=i=0∑n(in)a(n−i)bia=21a,b=32a54
=i=0∑12(i12)(21a)(12−i)(32a54)i
総和を展開する
=0!(12−0)!12!(21a)12(32a54)0+1!(12−1)!12!(21a)11(32a54)1+2!(12−2)!12!(21a)10(32a54)2+3!(12−3)!12!(21a)9(32a54)3+4!(12−4)!12!(21a)8(32a54)4+5!(12−5)!12!(21a)7(32a54)5+6!(12−6)!12!(21a)6(32a54)6+7!(12−7)!12!(21a)5(32a54)7+8!(12−8)!12!(21a)4(32a54)8+9!(12−9)!12!(21a)3(32a54)9+10!(12−10)!12!(21a)2(32a54)10+11!(12−11)!12!(21a)1(32a54)11+12!(12−12)!12!(21a)0(32a54)12
簡素化 0!(12−0)!12!(21a)12(32a54)0:4096a6
簡素化 1!(12−1)!12!(21a)11(32a54)1:256a54(a)11
簡素化 2!(12−2)!12!(21a)10(32a54)2:38411a533
簡素化 3!(12−3)!12!(21a)9(32a54)3:43255a1069
簡素化 4!(12−4)!12!(21a)8(32a54)4:14455a536
簡素化 5!(12−5)!12!(21a)7(32a54)5:2722a4(a)7
簡素化 6!(12−6)!12!(21a)6(32a54)6:243308a539
簡素化 7!(12−7)!12!(21a)5(32a54)7:243352a1081
簡素化 8!(12−8)!12!(21a)4(32a54)8:729880a542
簡素化 9!(12−9)!12!(21a)3(32a54)9:1968314080a1087
簡素化 10!(12−10)!12!(21a)2(32a54)10:196835632a9
簡素化 11!(12−11)!12!(21a)1(32a54)11:590494096a1093
簡素化 12!(12−12)!12!(21a)0(32a54)12:5314414096a548
=4096a6+256a54(a)11+38411a533+43255a1069+14455a536+2722a4(a)7+243308a539+243352a1081+729880a542+1968314080a1087+196835632a9+590494096a1093+5314414096a548
簡素化 4096a6+256a54(a)11+38411a533+43255a1069+14455a536+2722a4(a)7+243308a539+243352a1081+729880a542+1968314080a1087+196835632a9+590494096a1093+5314414096a548:4096a6+256a1063+38411a533+43255a1069+14455a536+2722a215+243308a539+352a1081+729880a542+1968314080a1087+5632a9+590494096a1093+5314414096a548
=4096a6+256a1063+38411a533+43255a1069+14455a536+2722a215+243308a539+352a1081+729880a542+1968314080a1087+5632a9+590494096a1093+5314414096a548