erweitern (2-2x)e^{2x-x^2-4y-y^2=0}

Lösung

erweitern

(2 - 2 x) e^{2 x - x^{2} - 4 y - y^{2} = 0}

2 e^{2 x - x^{2} - 4 y - 0 = y^{2}} - 2 e^{2 x - x^{2} - 4 y - 0 = y^{2}} x

Schritte zur Lösung

(2 - 2 x) e^{2 x - x^{2} - 4 y - y^{2} = 0}

= e^{2 x - x^{2} - 4 y - 0 = y^{2}} (2 - 2 x)

Wende das Distributivgesetz an:

a (b - c) = ab - a c

a = e^{2 x - x^{2} - 4 y - y^{2} = 0}, b = 2, c = 2 x

= e^{2 x - x^{2} - 4 y - y^{2} = 0} \cdot 2 - e^{2 x - x^{2} - 4 y - y^{2} = 0} \cdot 2 x

= 2 e^{2 x - x^{2} - 4 y - 0 = y^{2}} - 2 e^{2 x - x^{2} - 4 y - 0 = y^{2}} x

e x p an d, (\frac{1}{44 + 210 j} + \frac{1}{50 + 80 j})

s im pl i f y (2 t cos (5 t) + 3 t sinh (t)) (s)

e x p an d (x^{2} - x) e^{2 x}

s im pl i f y 4 (2 w - \frac{315}{w ^{2}})

e x p an d - c b^{\frac{5}{2}} (- \frac{e ^{- \frac{r}{a}} r ^{2}}{a} + 2 e^{- \frac{r}{a}} r)