展开 ((3x-2)^2)/9

解答

展开

\frac{( 3 x - 2 ) ^{2}}{9}

x^{2} - \frac{4 x}{3} + \frac{4}{9}

求解步骤

\frac{( 3 x - 2 ) ^{2}}{9}

(3 x - 2)^{2} = 9 x^{2} - 12 x + 4

= \frac{9 x ^{2} - 12 x + 4}{9}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 x ^{2} - 12 x + 4}{9} = \frac{9 x ^{2}}{9} - \frac{12 x}{9} + \frac{4}{9}

= \frac{9 x ^{2}}{9} - \frac{12 x}{9} + \frac{4}{9}

数字相除:

\frac{9}{9} = 1

= x^{2} - \frac{12 x}{9} + \frac{4}{9}

消掉

\frac{12 x}{9} : \frac{4 x}{3}

= x^{2} - \frac{4 x}{3} + \frac{4}{9}

e x p an d cos^{2} (x) (sec^{2} (x) + csc^{2} (x))

e x p an d \frac{3 ( - y + 31 )}{2}

e x p an d (- 1 + \frac{- i}{n})^{2}

e x p an d (3 π (1 - t) + 3) (- \frac{π}{2})

e x p an d \frac{2 ( 3 - 2 46 )}{5}