展开 (1+ac)(be-bd)

解答

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(1 + a c) (b e - b d)

e b - b d + e a c b - a c b d

求解步骤

(1 + a c) (b e - b d)

= (1 + a c) (e b - b d)

使用 FOIL 方法:

(a + b) (c + d) = a c + a d + b c + b d

a = 1, b = a c, c = b e, d = - b d

= 1 \cdot b e + 1 \cdot (- b d) + a c b e + a c (- b d)

使用加减运算法则

+ (- a) = - a

= 1 e b - 1 \cdot b d + e a c b - a c b d

化简

1 e b - 1 \cdot b d + e a c b - a c b d : e b - b d + e a c b - a c b d

= e b - b d + e a c b - a c b d

e x p an d (6 x - 1)^{3}

e x p an d - \frac{2}{3} (4 x + 6 y = 33)

e x p an d 4 (4 - π) c m^{2}

e x p an d \frac{( - 1 ) ^{n} n !}{2 ^{n} ( n + 1 )}

e x p an d \frac{- 2 x - 10}{( x + 3 ) ( x + 1 )}