解
簡約 h(x+h)5−x5
解
5x4+10x3h+10x2h2+5xh3+h4
解答ステップ
h(x+h)5−x5
因数 (x+h)5−x5:h((x+h)4+x(x+h)3+x2(x+h)2+x3(x+h)+x4)
=hh((x+h)4+x(x+h)3+x2(x+h)2+x3(x+h)+x4)
共通因数を約分する:h=(x+h)4+x(x+h)3+x2(x+h)2+x3(x+h)+x4
(x+h)4:x4+4x3h+6x2h2+4xh3+h4
=x4+4x3h+6x2h2+4xh3+h4+x(x+h)3+x2(x+h)2+x3(x+h)+x4
(x+h)3:x3+3x2h+3xh2+h3
=x4+4x3h+6x2h2+4xh3+h4+x(x3+3x2h+3xh2+h3)+x2(x+h)2+x3(x+h)+x4
(x+h)2:x2+2xh+h2
=x4+4x3h+6x2h2+4xh3+h4+x(x3+3x2h+3xh2+h3)+x2(x2+2xh+h2)+x3(x+h)+x4
拡張 x(x3+3x2h+3xh2+h3):x4+3x3h+3x2h2+xh3
=x4+4x3h+6x2h2+4xh3+h4+x4+3x3h+3x2h2+xh3+x2(x2+2xh+h2)+x3(x+h)+x4
拡張 x2(x2+2xh+h2):x4+2x3h+x2h2
=x4+4x3h+6x2h2+4xh3+h4+x4+3x3h+3x2h2+xh3+x4+2x3h+x2h2+x3(x+h)+x4
拡張 x3(x+h):x4+x3h
=x4+4x3h+6x2h2+4xh3+h4+x4+3x3h+3x2h2+xh3+x4+2x3h+x2h2+x4+x3h+x4
簡素化 x4+4x3h+6x2h2+4xh3+h4+x4+3x3h+3x2h2+xh3+x4+2x3h+x2h2+x4+x3h+x4:5x4+10x3h+10x2h2+5xh3+h4
=5x4+10x3h+10x2h2+5xh3+h4