d/(dq)((c)(0.0003q^2-0.03q+4))

Lösung

\frac{d}{d q} ((c) (0.0003 q^{2} - 0.03 q + 4))

c (0.0006 q - 0.03)

Schritte zur Lösung

\frac{d}{d q} ((c) (0.0003 q^{2} - 0.03 q + 4))

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= c \frac{d}{d q} (0.0003 q^{2} - 0.03 q + 4)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= c (\frac{d}{d q} (0.0003 q^{2}) - \frac{d}{d q} (0.03 q) + \frac{d}{d q} (4))

\frac{d}{d q} (0.0003 q^{2}) = 0.0006 q

\frac{d}{d q} (0.03 q) = 0.03

\frac{d}{d q} (4) = 0

= c (0.0006 q - 0.03 + 0)

Vereinfache

= c (0.0006 q - 0.03)

e x p an d (3 + 5) (6 + 5)

e x p an d \frac{x d x}{( x ^{2} - 1 ) ^{3}}

s im pl i f y 2 (\frac{2}{35} - s t)

e x p an d - 2 (x + π)^{2}

e x p an d \frac{1}{x ^{2} ( c x + 1 )}