展开 (2x^2+4x+3)/((x+1)^2(x^2-4s+13))

解答

展开

\frac{2 x ^{2} + 4 x + 3}{( x + 1 ) ^{2} ( x ^{2} - 4 s + 13 )}

\frac{2 x ^{2} + 4 x + 3}{- 4 x ^{2} s + x ^{4} + 14 x ^{2} + 2 x ^{3} - 8 x s + 26 x - 4 s + 13}

求解步骤

\frac{2 x ^{2} + 4 x + 3}{( x + 1 ) ^{2} ( x ^{2} - 4 s + 13 )}

(x + 1)^{2} = x^{2} + 2 x + 1

= \frac{2 x ^{2} + 4 x + 3}{( x ^{2} + 2 x + 1 ) ( x ^{2} + 13 - 4 s )}

乘开

(x^{2} + 2 x + 1) (x^{2} - 4 s + 13) : - 4 x^{2} s + x^{4} + 14 x^{2} + 2 x^{3} - 8 x s + 26 x - 4 s + 13

= \frac{2 x ^{2} + 4 x + 3}{- 4 x ^{2} s + x ^{4} + 14 x ^{2} + 2 x ^{3} - 8 x s + 26 x - 4 s + 13}

e x p an d (3 + cos (θ))^{2}

e x p an d (t + 1) i

e x p an d (3 + cos (θ))^{3}

\frac{d ^{2}}{d y ^{2}} ((S) (3 - \frac{147}{y ^{2}}))

e x p an d (4 x^{2} + 5 x + 5)^{5}