展开 sin(x)(tan(x)+1)(tan(x)-1)

解答

展开

sin (x) (tan (x) + 1) (tan (x) - 1)

tan^{2} (x) sin (x) - sin (x)

求解步骤

sin (x) (tan (x) + 1) (tan (x) - 1)

展开

sin (x) (tan (x) + 1) (tan (x) - 1) : sin (x) (tan^{2} (x) - 1)

= sin (x) (tan^{2} (x) - 1)

使用分配律:

a (b - c) = ab - a c

sin (x) (tan^{2} (x) - 1) = sin (x) tan^{2} (x) - sin (x) \cdot 1

= sin (x) tan^{2} (x) - sin (x) \cdot 1

化简

sin (x) tan^{2} (x) - sin (x) \cdot 1 : tan^{2} (x) sin (x) - sin (x)

= tan^{2} (x) sin (x) - sin (x)

e x p an d (4 - 3 i) l e f t (5 - i) l e f t (1 + i)

e x p an d 6 (\frac{1}{2})^{4} + 2 (\frac{1}{2})^{3} - 12 (\frac{1}{2})^{2} + 3

e x p an d \frac{( s + 0.1 ) ( s + 500 )}{( s + 30 ) ^{2}}

e x p an d ro t a c i o na l (x^{2} - 2 y^{2} + 4)

e x p an d 2 (X + 3)