erweitern (2x^4-1)'(5x^3-6)+(5x^3-6)'(2x^4-1)

Lösung

erweitern

(2 x^{4} - 1)^{'} \cdot (5 x^{3} - 6) + (5 x^{3} - 6)^{'} \cdot (2 x^{4} - 1)

5 x^{3} (2 x^{4} - 1)' - 6 (2 x^{4} - 1)' + 2 x^{4} (5 x^{3} - 6)' - (5 x^{3} - 6)'

Schritte zur Lösung

(2 x^{4} - 1)^{'} (5 x^{3} - 6) + (5 x^{3} - 6)^{'} (2 x^{4} - 1)

Multipliziere aus

(2 x^{4} - 1)^{'} (5 x^{3} - 6) : 5 x^{3} (2 x^{4} - 1)^{'} - 6 (2 x^{4} - 1)^{'}

= 5 x^{3} (2 x^{4} - 1)^{'} - 6 (2 x^{4} - 1)^{'} + (5 x^{3} - 6)^{'} (2 x^{4} - 1)

Multipliziere aus

(5 x^{3} - 6)^{'} (2 x^{4} - 1) : 2 x^{4} (5 x^{3} - 6)^{'} - (5 x^{3} - 6)^{'}

= 5 x^{3} (2 x^{4} - 1)^{'} - 6 (2 x^{4} - 1)^{'} + 2 x^{4} (5 x^{3} - 6)^{'} - (5 x^{3} - 6)^{'}

e x p an d - K L + (U (t - \frac{e ^{x t} - 1}{x}))

s im pl i f y (2 - 3) (2 + 46)

e x p an d (\frac{n}{2} - \frac{2}{n})^{2}

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e x p an d (2 + 1) (3 + 1)