erweitern ((4x+12)^2)/4+((y-4)^2)/4

Lösung

erweitern

\frac{( 4 x + 12 ) ^{2}}{4} + \frac{( y - 4 ) ^{2}}{4}

4 x^{2} + 24 x + \frac{y ^{2}}{4} + 40 - 2 y

Schritte zur Lösung

\frac{( 4 x + 12 ) ^{2}}{4} + \frac{( y - 4 ) ^{2}}{4}

Wende Regel an

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{( 4 x + 12 ) ^{2} + ( y - 4 ) ^{2}}{4}

Multipliziere aus

(4 x + 12)^{2} + (y - 4)^{2} : 16 x^{2} + 96 x + y^{2} + 160 - 8 y

= \frac{16 x ^{2} + 96 x + y ^{2} + 160 - 8 y}{4}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 x ^{2} + 96 x + y ^{2} + 160 - 8 y}{4} = \frac{16 x ^{2}}{4} + \frac{96 x}{4} + \frac{y ^{2}}{4} + \frac{160}{4} - \frac{8 y}{4}

= \frac{16 x ^{2}}{4} + \frac{96 x}{4} + \frac{y ^{2}}{4} + \frac{160}{4} - \frac{8 y}{4}

\frac{16 x ^{2}}{4} = 4 x^{2}

\frac{96 x}{4} = 24 x

\frac{160}{4} = 40

\frac{8 y}{4} = 2 y

= 4 x^{2} + 24 x + \frac{y ^{2}}{4} + 40 - 2 y

e x p an d (t - a) (H (t - a) - H (t - b))

e x p an d \frac{( 8 - x )}{( x + 2 ) ^{2}}

e x p an d (x - 4) 3 x

e x p an d x^{2} y^{''} (x) + x (x + 2) y^{'} (x) - (x + 2) y

e x p an d \frac{2 e ^{- s}}{s ^{3} ( s + 1 )}