vereinfachen (x+4)(x+1-3i)^2

Lösung

vereinfachen

(x + 4) (x + 1 - 3 i)^{2}

(x^{3} + 6 x^{2} - 32) + (- 24 - 30 x - 6 x^{2}) i

Schritte zur Lösung

(x + 4) (x + 1 - 3 i)^{2}

= (x + 1 - 3 i)^{2} (x + 4)

Wende das Distributivgesetz an:

a (b + c) = ab + a c

(x + 1 - 3 i)^{2} (x + 4) = (x + 1 - 3 i)^{2} x + (x + 1 - 3 i)^{2} \cdot 4

= (x + 1 - 3 i)^{2} x + (x + 1 - 3 i)^{2} \cdot 4

Vereinfache

(x + 1 - 3 i)^{2} x + (x + 1 - 3 i)^{2} \cdot 4 : - 24 i + x^{3} + 6 x^{2} - 30 x i - 6 x^{2} i - 32

= - 24 i + x^{3} + 6 x^{2} - 30 x i - 6 x^{2} i - 32

Rewrite in standard complex form:

(x^{3} + 6 x^{2} - 32) + (- 24 - 30 x - 6 x^{2}) i

= (x^{3} + 6 x^{2} - 32) + (- 24 - 30 x - 6 x^{2}) i

e x p an d \frac{( 0.00115 + x ) \cdot x}{0.011 - x}

e x p an d (1 + (\frac{4 x}{1 - 4 x})) (x (1 - 4 x))

e x p an d \frac{\frac{d}{d x} ( ( 3 x - 2 ) 3 )}{2}

s im pl i f y 2 (7 - 2)

e x p an d A (3, - 4) y B (5, 1)