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受欢迎的代数 >

10g^2+10=29g

解答

10 g^{2} + 10 = 29 g

解答

g = \frac{5}{2}, g = \frac{2}{5}

+1

十进制

g = 2.5, g = 0.4

求解步骤

10 g^{2} + 10 = 29 g

将

29 g

para o lado esquerdo

10 g^{2} + 10 - 29 g = 0

改写成标准形式

a x^{2} + b x + c = 0

10 g^{2} - 29 g + 10 = 0

使用求根公式求解

g_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

(- 29)^{2} - 4 \cdot 10 \cdot 10 = 21

g_{1, 2} = \frac{- ( - 29 ) \pm 21}{2 \cdot 10}

将解分隔开

g_{1} = \frac{- ( - 29 ) + 21}{2 \cdot 10}, g_{2} = \frac{- ( - 29 ) - 21}{2 \cdot 10}

g = \frac{- ( - 29 ) + 21}{2 \cdot 10} : \frac{5}{2}

g = \frac{- ( - 29 ) - 21}{2 \cdot 10} : \frac{2}{5}

二次方程组的解是:

g = \frac{5}{2}, g = \frac{2}{5}

作图

流行的例子

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