(\partial)/(\partial y)((m)(x+y)dx)

解答

\frac{\partial}{\partial y} ((m) (x + y) d x)

m x d

求解步骤

\frac{\partial}{\partial y} ((m) (x + y) d x)

将

m, x, d

视为常数

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= m d x \frac{\partial}{\partial y} (x + y)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= m d x (\frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (y))

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (y) = 1

= m d x (0 + 1)

化简

= m x d

e x p an d \frac{lo g _{10} ( x ) ( x ^{2} + 6 ) - 1}{2}

e x p an d (2 + 5) (3 + 7)

e x p an d \frac{( 3 - 2 j ) ( 8 + 10 j )}{( 11 + 8 i )}

e x p an d \frac{( 2 - x ) ^{3} \cdot ( 9 - x ) ^{5}}{( x ^{2} + 8 ) ^{2}}

e x p an d \frac{7 ( n + 1 ) ^{2}}{4 n}