erweitern ((x^2+4x+3)(x+1))/(36)

Lösung

erweitern

\frac{( x ^{2} + 4 x + 3 ) ( x + 1 )}{36}

\frac{x ^{3}}{36} + \frac{5 x ^{2}}{36} + \frac{7 x}{36} + \frac{1}{12}

Schritte zur Lösung

\frac{( x ^{2} + 4 x + 3 ) ( x + 1 )}{36}

Multipliziere aus

(x^{2} + 4 x + 3) (x + 1) : x^{3} + 5 x^{2} + 7 x + 3

= \frac{x ^{3} + 5 x ^{2} + 7 x + 3}{36}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} + 5 x ^{2} + 7 x + 3}{36} = \frac{x ^{3}}{36} + \frac{5 x ^{2}}{36} + \frac{7 x}{36} + \frac{3}{36}

= \frac{x ^{3}}{36} + \frac{5 x ^{2}}{36} + \frac{7 x}{36} + \frac{3}{36}

Streiche

\frac{3}{36} : \frac{1}{12}

= \frac{x ^{3}}{36} + \frac{5 x ^{2}}{36} + \frac{7 x}{36} + \frac{1}{12}

e x p an d f (x) 3 t + 4 (g (x, t) = - 3)

e x p an d \frac{1}{( 1 - 5 x ) ^{- \frac{1}{4}}}

e x p an d (sin (a) + cos (b)) (sin (b) + cos (a))

e x p an d p^{\frac{1}{4}} (p^{\frac{3}{4}} + 3 p^{\frac{7}{4}})

e x p an d A (- 2, 22) B (13, - 19)