展開する (20G(C)-80C=4,6)(100G(C)-160C=140)

解

展開する

(20 G (C) - 80 C = 4, 6) (100 G (C) - 160 C = 140)

2000 G (C)^{2} - 3200 CG (C) = 140

解答ステップ

(20 G (C) - 80 C = 4, 6) (100 G (C) - 160 C = 140)

= (20 G (C) - 80 \cdot 4 \cdot 6 =, C) (100 G (C) - 160 \cdot 140 = C)

FOIL メソッドを適用する:

(a + b) (c + d) = a c + a d + b c + b d

a = 20 G (C), b = - 80 C = 4, 6, c = 100 G (C), d = - 160 C = 140

= 20 G (C) \cdot 100 G (C) + 20 G (C) (- 160 C = 140) + (- 80 C = 4, 6) \cdot 100 G (C) + (- 80 C = 4, 6) (- 160 C = 140)

マイナス・プラスの規則を適用する

+ (- a) = - a, (- a) (- b) = ab

20 \cdot 100 G (C) G (C) - 20 \cdot 160 CG (C) = 140 - 80 C = 4, 6 \cdot 100 G (C) + 80 C = 4, 6 \cdot 160 C = 140

拡張

20 \cdot 100 G (C) G (C) - 20 \cdot 160 CG (C) : 2000 G (C)^{2} - 3200 CG (C)

2000 G (C)^{2} - 3200 CG (C) = 140